Cov(f(X),g(Y))≤|β|√Var(f(X))Var(g(Y)).
In fact, one can define the maximal correlation of random variable by the best constant above and of course it should be bigger than β. Let us remark how to prove the inequality above quickly. We can use the expansion by Hermit polynomial that we have
E[Hn(X)Hm(Y)]=δn,m(E1n![XY])n.
Then a centered L2 functions have projection on H0 zero. Then we have
E[f(X)g(Y)]=∞∑n=1⟨f,Hn⟩⟨g,Hn⟩1n!βn≤|β|√∞∑n=1⟨f,Hn⟩21n!√∞∑n=1⟨g,Hn⟩21n!≤β|√Var(f(X))Var(g(Y)).
This concludes the proof.
This concludes the proof.
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