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2017年4月2日星期日

Percolation (1) : 2D Bernoulli percolation, critical point and transition of phase

Recently I attend the seminar talking about the percolation theory in IHES so I wrote some notes here.

Before starting, we have to notice that the terminology of percolation is adopted in different situations and generally in the contexts of graphs - it could be various graphs - like lattice Zd, random graphs, random maps etc. But the phenomena is a little universal that a path starts from 0 and goes to infinite faraway. In this series of talk, Hugo focuses on the situation of 2D Bernoulli percolation.

Definition and critical point

We give some definitions precisely. In the lattice graph Z2, each site has 4 neighbors and every edge has independently a probability p to be present (open) or a probability 1p to be absent (closed). Then there exits a critical point pc : when ppc, with probability 0 there exists a path from 0 to , while when p>pc, with probability θ(p) there exists a path from 0 to .

ppc,θ(p)=P[0]=0p>pc,θ(p)=P[0]>0

In 2D model, the critical point pc=1/2. Some simple argument supports this point. For example, if we draw the dual percolation between the face whose frontier is closed, we get a dual graph with probability 1p. If we suppose that the critical point is unique, then the transition of face happens at the same time in both the primal graph and the dual graph. So pc=1pc and pc=1/2.


Quantitative analysis 

We hope to get some stronger result, The following theorem is first obtained by Menshikov, Aizeman and Michael p<pc,Cp>0 s.t Pp[0Bn]exp(Cpn)p>pc,C>0 s.t Pp[0]C(ppc)

Here, we denote the ball of radius n by Bn and this theorem indeed, gives some numerical estimation of the speed of decrements. 

Proof 1 by (Menshikov, Aizeman, Michael) 

We note θn(p)=Pp[0Bn] and ϕp(S)=xS,yS,xypP[0Sx]. We can prove it by 5 steps.

  1.  We admit at first this important inequalityddpθn(p)1p(1p)[inf0SBnϕp(S)](1θn(p))
    then we define ˜pc=sup{p:S0,s.tϕp(S)<1}
    we can prove θ(P)1p(1˜pc)(p˜pc)
  2.  We choose SBk1 such that ϕp(S)<1 and proveθnk(p)(ϕp(S))n
  3. We conclude that ˜pc=pc
  4. Verify the identity ddpPp(X)=eE1p(1p)Cov(we,X)
  5. We put X=I0!Bn and we prove the important inequality.


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